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Three resistors each of 39 Ohms are hooked up in series to a 7 V battery....

Three resistors each of 39 Ohms are hooked up in series to a 7 V battery. What is the voltage drop across each resistor in volts?

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Answer #1

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Answer #2

volatge will divide equally to all resistance

V = Vtotal/3
   =7/3 V
   =2.33 V

Ans: 2.33 V

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Answer #3

\\equivalent\:resistance=36+36+36=108ohms\\ current\:across\;each\:resistor(i)=V/R=7/108\\ voltage\:drop\:across\:each\;resistor(V)=Ri =\frac{7}{108}*36\\ =7/3V

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