Question

Suppose that the distribution of IQ scores (X) of a group of school children follows the normal distribution of with an unknown mean and an standard deviation z. A random sample of n=16 children from this population resulted in sample mean x=105 and sample standard deviation S=16. The Kolmogrov-Rao-Blackwell-Pathak estimator of the proportion population with an IQ of at most 111 is:

A: 0.671

B: 0.693

C: 0.648

D: 0.715

E: 0.624

Answer 1

Criven, n=16 x= 105 s= 16 we have to find, PCX5 111) = P(Pets 11.-*) - Plzs 111-105) 16 = P(Z < 0.38) - 10.648) option (C) y correct. CS Scanned with CamScanner