1 5 P A 0.111 kg rock is attached to a 2.06 m long string and...

Question

Question

science physics

Answer 1

Answer #1

Solution,

Tension, T = mv^2/r

T = (0.111 x 32.1^2)/2.06 = 55.52 N

Comment in case any doubt please rate my answer.....

Answer 2

Similar Homework Help Questions

A rock of mass m = 0.97 kg is attached to a massless string of length...

A rock of mass m = 0.97 kg is attached to a massless string of length L = 0.71 m. The rock is swung in a vertical circle faster and faster up to a speed of v = 2.4 m/s, at which time the string breaks. What is the magnitude of the tension, in newtons, at which the string breaks?
0/1 pts Question 5 A rock of mass 4 kg is twirled around a string of...

0/1 pts Question 5 A rock of mass 4 kg is twirled around a string of radius 2 m with a speed of 10 m/s. Determine the tension (units of Newtons) in the string (neglect gravity). er 200 margin of error +/- 5%
A 0.2 kg tennis ball attached to a 2 m long string is being swung in...

A 0.2 kg tennis ball attached to a 2 m long string is being swung in a horizontal plane at 200rpm, what is the tension in the string? please help, my professor got 175 N but i am not sure how.

A 0.2 kg tennis ball attached to a 2 m long string is being swung in...

A 0.2 kg tennis ball attached to a 2 m long string is being swung in a horizontal plane at 200rpm, what is the tension in the string? please help, my professor got 175 N but i am not sure how.
A mass of 0.875 kg, on a frictionless table, is attached to a string which passes...

A mass of 0.875 kg, on a frictionless table, is attached to a string which passes through a hole in the table. The hole is at the center of a horizontal circle in which the mass moves with constant speed. The radius of the circle is 0.520 m and the speed of the mass is 17.0 m/s. It is found that drawing the string down through the hole and reducing the radius of the circle to 0.370 m has the...
7, A 25 g ball is attached to a 0.5 m long string and swung in...

7, A 25 g ball is attached to a 0.5 m long string and swung in a circle as shown below a. Calculate the tension in the string. (2 marks) b. Calculate the centripetal force. (1 mark) c. Calculate the speed of the ball. (3 marks) d. Calculate the period of the ball's rotation. (1 mark) e. If the ball was spun faster, what would happen to the radius of the ball's path? (1 mark)

A stone with a mass of 0.700 kg is attached to one end of a string...

A stone with a mass of 0.700 kg is attached to one end of a string 0.800 m long. The string will break if its tension exceeds 50.0 N. The stone is whirled in a horizontal circle on a frictionless tabletop; the other end of the string remains fixed. A. Find the maximum speed the stone can attain without breaking the string.
3.0 m 7. A 3.0-kg is attached to the end of a 3.0-m long string. It...

3.0 m 7. A 3.0-kg is attached to the end of a 3.0-m long string. It is held in the horizontal position (as shown) and released. a) What is the speed of the mass as it passes through the lowest position? b) What is the tension in the string as it passes through the lowest position?
A 1.0 kg object is attached to one end of a 1.25 m long string. The...

A 1.0 kg object is attached to one end of a 1.25 m long string. The other end of the string is fixed. The object is released from rest when the string is horizontal falls to a vertical 90-degree angle. What is the speed of the object as the lowest point along the path (when the string is vertical)? What is the value of the tension in the string at the lowest point? What is the work done by the...

4. -2 points PSE6 6.P.011 My Notes A 3.90 kg object is attached to a vertical...

4. -2 points PSE6 6.P.011 My Notes A 3.90 kg object is attached to a vertical rod by two strings as in Figure P6.11. The object rotates in a horizontal circle at constant speed 7.10 m/s. 00 m 3.00 m 00 m Figure P6.11 (a) Find the tension in the upper string (b) Find the tension in the lower string