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Problem 10-23 Suppose your manager presents you with the following Information about machines that could be used for a job, a

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Answer #1

Process Capacity = USL - LSL/ 7* Standard deviation

USL= upper specifications width

LSL= Lower specifications width

USL-LSL= 0.48

Each process Capacity:

A= 0.48/(6*.058)= 0.48/0.348

= 1.38

B= 0.48/(6*.060)= 0.48/0.360

= 1.33

C= 0.48/(6*0.073)= 0.48/0.438

=1.10

D= 0.48/(6*0.062)= 0.48/372

D= 1.29

Process C has least capacity ratio 1.10 so we can narrow process C.

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