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- 2019 Seved Help Save & Exit Suppose your manager presents you with the following information about machines that could be u
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Answer #1

Cp = Specification width/(6*standard deviation)

Processes Cp values are:

A = 0.48/(6*0.057) = 1.404

B = 0.48/(6*0.060) = 1.333

C = 0.48/(6*0.063) = 1.270

D = 0.48/(6*0.064) = 1.250

So, we can narrow choice to Process A although the cost is highest

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