Homework Answers
Magnetic force on a moving charge q with a velocity v in a magnetic field B is given by
F = qvB sin 
Where
- Angle between v and B.
Given that the charge is moving parallel to the magnetic field.
Hence
= 0 degree or
= 180 degree
In both case Sin
= 0
Hence the magnetic force is 0 Newton.
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A positively charged particle moving parallel to the x-axis
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the figure below
in the y-direction, and ˆk is in the z-direction. What is the
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low. Figure: î is in the x-direction, ſ is
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with constant velocity in the y-direction enters a region
containing a constant magnetic field B = 1T aligned with the
positive z-axis as shown. The particle enters the region at (x,y) =
(0.68 m, 0) and leaves the region at (x,y) = 0, 0.68 m a time t =
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