Question

Mis L- Fig. 9-28 Fig. 9-29 9.33. Determine the equation of the deflection curve for the cantilever beam loaded by the concentrated force P as shown in Fig. 9-28. Ans. Ely = -(a – )3 – Pa< x + Pas for 0 << <a; Ely = - Pą2 x + Pap for a < < <L 9.34. For the cantilever beam of Fig. 9-28, take P = 1000 lb, a = 6 ft, and b = 4 ft. The beam is of equilateral triangular cross-section, 6 in. on a side, with a vertical axis of symmetry. Determine the maximum deflection of the beam. Take E= 30 X 106 lb/in2. Ans. -0.355 in. 9.35. Refer to Fig. 9-29. Find the equation of the deflection curve for the cantilever beam loaded by the couple M. Ans. Ely = -M.2/2 for 0 < x <a; Ely = -Max + (M_a2/2) for a <3 <L

Please answer question 9.35.

Answer 1

=> 63 Lite - Metas a Elly=- Mizh teputer ܩܒܛܘܫܝܘ ܂ ܘܡܟ at x=0; y no 37930 i for oszca ; lytis [More] e for oarca ; for a<x<L Body-MX+M. (ka) Esday - MX+ M, Cx-) +as Elya-madi + My Cx +Cjxt</ at 1209 20 2) 420 Totxe => 428 for acast seldi. = 41 et 220 m - m = G =-Ma 2) Eys - Omax + at x2a; y==ma 2 ay C2 = Mat Ely=-M, ax +M, 92 - Fleese live pecting