The Newton gravitational force F = Gm1m2/r2
is called an inverse square force. Which of the following would be the reason for it being called that? Input the letter corresponding to the correct answer in the format "X" where X is the letter corresponding to the correct answer choice.
A. The formula contains a constant G. This is the reason.
B. The Force depends linearly on any one of the masses,
C. The Force varies as 1/the distance squared.
D. The Force varies as the mass squared.
E. There is no such thing as an inverse square force
C. The force varies as 1/(the distance squared)
Gravitational force is inversely proportional to square of the distance between two masses

The Newton gravitational force F = Gm1m2/r2 is called an inverse square force. Which of...
Adding to Newton’s law of universal gravitation, the gravitational force between two masses is proportional to 1/r^2, where r is the distance between the masses. Surprisingly, the electric force between two electric charges is also proportional to 1/r^2, where r is the distance between the electric charges. (Coulomb’s law) These facts are called the “inverse-square laws” -> Now give “your answer” to the question: Why (or How) are these forces proportional to 1/r^2 (not 1/r, 1/r^3, 1/r^100, etc)?
Problem: Write a program to calculate the force of gravitational attraction between two objects of known mass at a known distance. Use the formula developed by Isaac Newton known as Law of Universal Gravitation. F G*m *m2/d2 Where F (Force of gravity) is expressed in Newtons (N), mi and m2 (masses of the objects) are expressed in kilograms (kgs) and d (distance from the center of one object to the center of the other) is expressed in meters (m) and...
Multivariable Calculus help with the magnitude of angular
momentum: My questions is exercise 4 but I have attached exercise 1
and other notes that I was provided
4 Exercise 4. In any mechanics problem where the mass m is constant, the position vector F sweeps out equal areas in equal times the magnitude of the angular momentum ILI is conserved (Note: be sure to prove "if and only if") (Note: don't try to use Exercise 2 in the proof of...
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