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A ABk A cKD A ABK Congruent witt A CD 1- Two sides in A ABk match two sides in A ckD and angle ohe 2- ASA 3- AAS 4-SSS witt T
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B A CKD In triangle LABK & » Z AKB =<CKD - I given and these opposite angle] - side Ak =KD are vertically [given]> fide Bk = CK Cgiven) so, the congruency rule will be side angle side [SAS] 1 Hence Proved Hope you like it please

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