Question

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In this lab, we first reacted ascorbic acid (vitamin C) with KIO, and KI. The reaction is as follows: Η HOH: C00 HOH C 0.0 1 + 3 + 2H+ + HOU ОНОН ascorbic acid HOT 0 0 dehydroascorbic acid This reaction is followed by titration with Na S,O; until the endpoint is reached. We reacted 500 L of 0.2 M KIO; (and excess KI) with an unknown quantity of vitamin C. We then titrated it with 0.2 M Na S,Oz. It required 500 ML of 0.2 M Na S,O; to reach the endpoint. How many grams of vitamin C were added in this reaction? (Molar mass of vitamin C = 176.12 g/mol) (Must show all calculation steps.)

Answer 1

IG + E +GHT - 317 + 3H₂O I Ascorbic acid ti tha Dehydroascable and +31 +247 - The excess I is Atrated with sg? Iz +25,002- I +692 0 Calcolate excess si the reaction I moles of 4 a 1x moles of so? txo-2m x 500uLXIOL ML sox 106 moles J-oxo moles Calculate Total moles I produced t moles of IG = 0.2m x 500 ML x 100 MC | According to reachion mole so co-oxo moles Io moles 2 1 lọc Ý tố ngle) 2 Kad 100x18 moles. I, give 3 moles In give a moles I z 3 x 10 xor : 30 x 105 moles produced Boxios moles Total moles to moles and moles of I reached with ascorbic 2 Toral moles - excess Z 3000 - 5x105 T25705 moles -

By reachon IT 70 moles of as couble auld a mees of I realed 2 258 10J moles mass of ascorbic acld con vitamin c z moles x molar mass 2 25x10 moles x 17 6-129 mol 20.04403.9 ~ 0-0 49 o-044G of vitamin C were added in this reaction.