2(NH4)3PO4 + 3 Pb(NO3)2 ------> 6NH4NO3 + Pb3(PO4)2 how may moles of (NH4)3NO3 would be required...

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Question

2(NH4)3PO4 + 3 Pb(NO3)2 ------> 6NH4NO3 + Pb3(PO4)2

how may moles of (NH4)3NO3 would be required to react with 9 moles of Pb(NO3)2?

science chemistry

Answer 1

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