Question

A 5μF capacitor is charged to 30 V and is then connected in series with a 10μH inductor and a 50Ω resistor. The initial current in the circuit will be

Correct answer is 0.600 A

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Answer 1

As clear from the diagram given below

30 V

Using KVL,

IR + L(dI/dt) = 30

But initially the current is minimum and hence dI/dt = 0 and hence

IR + L(0) = 30

IR = 30

I = 30/R

= 30/50

I = 0.600 A