Question

Four resistors are connected purely in parallel to a 7 volt battery. Three of the resistors are 3 ohms, 7 ohms, and 12 ohms, but the fourth is not initially known. The current out of the battery is 9 amps. What is the power dissipated from the fourth, unknown resistor, in Watts?

Four resistors are connected purely in parallel to a 7 volt battery. Three of the resistors are 3 ohms, 7 ohms, and 12 ohms, but the fourth is not initially known. The current out of the battery is 9 amps. What is the power dissipated from the fourth, unknown resistor, in Watts?

Answer 1

Req Ans. R=3 m2, R2=72, R₂ = 122, Ry I= Q H , v=7V Using Ohm's law a v=I Req = 7=9x Req Rea - Equivalent resistance of circuit = 0.7782 Also, R, Ra, Rz and Ry are connected in parallel - Reg kt Ret Ret Ry 0878 - 5 + + pe toate Ru= Resurtance of fourth resiston = 1.3782 Power dissipated from fourth unknown resistor 1.378 - Ry P = 35.56 W