You have subnetted a Class C address space of 220.55.66.0 using a subnet mask of 255.255.255.192. What is the useable address range for the first subnet?
A. 220.55.66.0 to 220.55.66.63
B. 220.55.66.0 to 220.55.66.62
C. 220.55.66.1 to 220.55.66.63
D. 220.55.66.1 to 220.55.66.62
D is correct. The subnet mask of 255.255.255.192 borrows the first two bits from the last octet. The first subnet is the 0 subnet, and the second is the 220.55.66.64 subnet. The relevant information regarding the first subnet is the subnet ID (220.55.66.0), the useable range (220.55.66.1 to 220.55.66.62), and the broadcast address (220.55.66.63).
A, B, and C are incorrect. These choices do not fall within the useable range.
You have subnetted a Class C address space of 220.55.66.0 using a subnet mask of 255.255.255.192....
A/ Given the following IP address from the Class B address range using the default subnet mask: 100.110.0.0. Your network plan requires no more than 64 hosts on a subnet. When you configure the IP address in Cisco IOS software, which value should you use as the subnet mask? 255.255.0.0 255.255.128.0 255.255.255.128 255.255.255.252 B/ Identify how many valid host addresses can you have on 192.168.27.32 network with a subnet mask of 255.255.255.240. (2^4) - 2 (2^3) – 2 (2^2)...
Q6: Subnet the Class C IP Address 195.1.1.0 So that you have 10 subnets each with a maximum 12 hosts on each subnet. List the Address on host 1 on subnet 0,1,2,3,10. Q7: Subnet the Class C IP Address 205.11.2.0 so that you have 30 subnets. · What is the subnet mask for the maximum number of hosts? · How many hosts can each subnet have? · What is the IP address of host 3 on subnet 2? Q8: You...
(8 points) A company has a network address of 178.145.20.64 with a subnet mask of 255.255.255.192. The company wants to break this address block into 4 subnets of equal size. a. What Subnet Mask should they configure on internal devices to achieve this? b. How many hosts per subnet do they obtain? c. List out the 4 Subnet IDs, the first and last valid host address, and the broadcast address for each of these subnets. 5. a. Subnet Mask: b....
You have a host device with an assigned IP address of 192.168.15.100 and a subnet mask of 255.255.255.192. To what network does this IP address belong? 192.168.15.0 192.168.15.16 192.168.15.32 192.168.15.64
(8 points) A company has a network address of 178.145.20.64 with a subnet mask of 255.255.255.192. The company wants to break this address block into 4 subnets of equal size. a. What Subnet Mask should they configure on internal devices to achieve this? b. How many hosts per subnet do they obtain? c. List out the 4 Subnet IDs, the first and last valid host address, and the broadcast address for each of these subnets. 5. a. Subnet Mask: b....
Consider you own the Class C network 192.168.3.0. You then decide utilize a subnet mask of 255.255.255.240 What are: a) The number of networks? b) The number of usable hosts/machine IPs per network? c) The full range of IPs of the first three networks? d) The usable IP address range from those first three networks
Scenario: IP Address: 192.168.1.0 Subnet Mask: 255.255.255.? What is the subnet mask need to be if we want to break up the IP Address space into 4 separate networks??
Given an IP address and mask of 192.168.10.0/24 255.255.255.0 (address / mask) subnet A has 100 hosts subnet b has 50 hosts Specification Subnet A Subnet B Number of bits in the subnet IP mask (binary) New IP mask (decimal) Maximum number of usable subnets (including the 0th subnet) Number of usable hosts per subnet IP Subnet First IP Host address Last IP Host address Description Subnet A Subnet B First IP address Last IP address Maximum number of hosts
If an IP address has a prefix /24, what would the subnet mask be? 255.255.255.224 255.255.0.0 255.0.0.0 255.255.255.192 255.255.255.0
using the information given below
. what is the ip address , subnet mask , default gateway?
** corrections
# of bits in subnet for A
:6
# of bits in submet for B:
3
PC-A
R1 G0/0
R GO/1
S1
PC-B ?
assign the IP ADDRESS information with given information
Given, IP address: 202.44.66.0/24 For Subnet A: It needs 2 valid hosts 2 valid hosts + 2 (network and broadcast) = 22 i.e., It needs 2 bit as host...