
A simply-supported beam is subjected to a combination of a distributed force and a concentrated force....
(1)20points 0.12m 0.05m The simply supported beam shown in the figure is subjected to a uniform transverse load and a concentrated load. (1.) Using two equal-length elements (FEM) to determine the deflection and stress of bottom surface. (2.) Using elementary beam theory to determine the deflection and stress of bottom surface
(1)20points 0.12m 0.05m The simply supported beam shown in the figure is subjected to a uniform transverse load and a concentrated load. (1.) Using two equal-length elements (FEM) to...
The simply supported beam, with a U cross section, is subjected to a uniformly distributed force of 8 kN/m and a concentrated load of 12 kN as shown. (a) Determine the reaction at supports A and B, (b) sketch the shear diagram and the moment diagram, (c) determine the location of the neutral axis of the cross section and calculate its area moment of inertia about the neutral axis, and (d) determine absolute maximum bending stress and (e) absolute maximum...
Problem 2 Consider a simply supported symmetric I beam ABCD carrying a uniformly distributed load w and a concentrated load F as shown in Figure 2. Young's modulus of the beam is 200 GPa F- 8 kNN 8cm 3cm 3cm w- 6 kN/m 6cm 2cm Figure 2 1) Replace the support C with the reaction force Rc, and using static equilibrium find the reactions at point A and B in terms of Ro 2) Using the boundary conditions, calculate the...
Problem 2 Consider a simply supported symmetric I beam ABCD carrying a uniformly distributed load w and a concentrated load F as shown in Figure 2. Young's modulus of the beam is 200 GPa. F 8 kN 8cm 3cm 3cm 7 m 5 m 3 m 2cm W= 6 kN/m 6cm A D B 2cm 7TITT TITIT Figure 2 1) Replace the support C with the reaction force Rc, and using static equilibrium find the reactions at point A and...
The simply supported beam of length L is subjected to uniformly distributed load of w and a vertical point load P at its middle, as shown in Figure Q3. Both young's modulus and second moment of area of this structure are given as E and I. Please provide your answers in terms of letters w, P,L,1, E. Self-weight of the beam is neglected. P W L/2 L/2 Figure Q3 (a) Determine the reactions, bending moment equation along the beam and...
16.6a) A simply supported beam is to span 15 ft. It will support a uniformly distributed load of 2 kips/ft over the full span and a concentrated load of 60 kips at mid-span. What is the required plastic section modulus Zx? (Include self-weight) 16.6b) A simply supported beam is to span 15 ft. It will support a uniformly distributed load of 2 kips/ft over the full span and a concentrated load of 60 kips at mid-span. Deflection is not to...
A simply supported beam as shown in the figure. The beam section is W18x211. The beam must support its own weight and must carry the following loading: Super-imposed distributed dead load = 0.25 kip/ft Distributed live load = 1 kip/ft Concentrated dead load = 12 kip The beam span L = 26 ft and the distance of the concentrated load from the right support a=6 ft. Consider analy- sis of beam subjected to load combination 1.2 dead + 1.6 live....
A simply supported beam AB is subjected to a triangle loading (see figure). The moment curvature equation is shown (from the left). The (El-constant) 1. Determine the deflection at middle beam. 2. Determine the rotation at middle beam. 2 kN/m B 4 m 8 EI 12 MacBook Air DOO 008 A tA % A - 5 & 7 6 I 0 * 8 9 R T
A simply supported beam AB is subjected to a triangle loading (see figure). The moment curvature equation is shown (from the left). The (El-constant) 1. Determine the deflection at middle beam. 2. Determine the rotation at middle beam. 2 kN/m A B 4.m x3 EI dx2 = - 2 COM MacBook Air 20 COD F4 FS F6 ►II # $ دیا 4 % 5 6 & 7 8 9
A simply supported beam AB is subjected to a triangle loading (see figure). The moment curvature equation is shown (from the left). The (El=constant) 1. Determine the deflection at middle beam. 2. Determine the rotation at middle beam. 2 kN/m A B 4 m d2v x3 ΕΙ = dx? 12 -x2+1