Question

1 points Use the following data to answer the next three questions. A group of students are classified according to their gender and major. The results of this classification is presented in the following table Marketing Finance Accounting Cis Total Female 45 50 60 190 Male 60 70 50610 110 130 85400 1. If a student is selected at random, what is the probability that this student is male given that this student is majoring in Marketing 0.40 0.60 0.075 043

Answer 1

☺ we need to find P[ Mall Slūdewt | Major is Marketing ] »» P[male Slideel. | Mgier w Marketing ] = f[Male Südent majoring in Marketing.) P[ Major in Marketing] Now, P[ Male Stüdeut majoring is Marketing ) = m( male majoring in Marketing) – Mama au crna - nl Sampie) Here, n[ Male majowing wis Marketing) = 30 m C Sample ) = 400 .. Son e(Male majesing w Marketing) = Now, PC Majors un Marketing) = n( major in Marketing) - 75 nisample) 400 where n(A) = number of an persons in event A re , P{male Suidet | Majør Marketiys = E 30/400 = 30 =0.4. 00 75 0 _ 24 (2) het x eleuate the littlīme dan electionic component 8.10 - XN Normal (1400, 600, thue n=25 & we need to find Plă <1300]. Suice x n Nomel (1400, 600%) so N N Nomal (1400,000 cs andnnez vithe -1400 NNCOL CamScanner 600/5 25 .

Le P[8<1800) = [- Kyoo < 130-1400) = P[22-0-833). 60015 600/5 ----Wheeing Slandard Normal Tables ef x < 1300] = P(Z <-0.833.)= 0.20.33 _ We know that_Margins of Error = 2XL where = sample size ra_populala slaždard dewakan 2 = 2-scare 1 for confidence level 95 %. now, o = 20 - 2-scool Margin of errar = 5 ü lg 6 Sot , 5 = 1.96 x 20 To = / 1096x20 ) 2 = n = 6105 ~ 62 cs Scanned with CamScanner