Treatment 1(x)
N1: 6
df1 = N - 1 = 6 - 1 = 5
M1: 2.1
SS1: 1.36
s21 =
SS1/(N - 1) = 1.36/(6-1) = 0.27
Treatment 2(y)
N2: 6
df2 = N - 1 = 6 - 1 = 5
M2: 5.62
SS2: 13.17
s22 =
SS2/(N - 1) = 13.17/(6-1) = 2.63
T-value Calculation
s2p =
((df1/(df1 +
df2)) * s21) +
((df2/(df2 +
df2)) * s22) =
((5/10) * 0.27) + ((5/10) * 2.63) = 1.45
s2M1 =
s2p/N1
= 1.45/6 = 0.24
s2M2 =
s2p/N2
= 1.45/6 = 0.24
t = (M1 -
M2)/√(s2M1
+ s2M2) =
-3.52/√0.48 = -5.05
The t-value is -5.0534. The p-value is .000248. The result is significant at p < .05.
ANSWERED
PLEASE RATE ME POSITIVE
THANKS
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