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86X212 (atomic mass = 211.99068 u) undergoes decay. Assuming all the released energy is in the...

86X212 (atomic mass = 211.99068 u) undergoes decay. Assuming all the released energy is in the form of kinetic energy of the particle (atomic mass = 4.002603 u) and ignoring the recoil of the daughter nucleus (84X1208 atomic mass = 207.98123 u), find the speed of the particle. Ignore relativistic effects. Number Units

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Solution:- The energy released in the reaction is, The change in mass is 211.99068 u-207.98123 u-4.002603 u 0.006847u Here, M

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