average atomicmass = (7-Li mass*percentage + 6-Li mass*percentage)/100
7-Li mass = 7 u
7-Li percentage = 92.41%
6-Li mass = 6 u
6-Li percentage = 7.59%
average Li-atomicmass = ((7*92.41)+(6*7.59))/(92.41+7.59)
= 6.924 u
No of mol of Li = w/at.wt
= 1.54/29.9
= 0.0515 mol
1 Li2O = 2 li atoms
No of mol of Li atoms = 0.0515*2 = 0.103 mol
No of mol of 6-Li atoms = 0.103*7.59/100 = 0.00782 mol
No of atoms of 6-Li = 0.00782 *6.023*10^23
= 4.71*10^21 atoms
answer: D
Student number: Name: Lithium has two stable isotopes with natural abundances of 92.41%ai Li). How many...
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