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Question 1 A 2.00 kg particle has the xy coordinates (-1.28 m, 0.164 m), and a 2.51 kg particle has the xy coordinates (0.806 m, -0.693 m). Both lie on a horizontal plane. At what (a) x and (b) y coordinates must you place a 3.07 kg particle such that the center of mass of the three-particle system has the coordinates (-0.942 m, -0.980 m)? (a) Number Units (b) Number Units Question Attempts: 0 of 12 used SAVE FOR LATER SUBMIT ANSWER

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Answer #1

a) Thex coordinates of the systems center of mass is. (2.00kg)(-1.28m)+(2.51kg) (0.806m) +(3.07kg)(x3 2.00 kg 2.51kg 3.07 kg

b) The y coordinates of the systems center of mass is, m +m+ma (2.00kg) (0.164m) (2.51kg)(-0.693m) +(3.07kg) (3) 2.00 kg 2.5

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