Question

Determine the kinetic energy of a gas at temperature 90 degree C, whose constituents are molecular oxygen. (O atomic number is 8, atomic mass is 16, 1 U=1.66 times 10^-27 kg

please show a solution

Answer 1

Question-8 : The kinetic energy of a gas at temperature 90 degree celsius, which is given as -

using an equation, we have

K.E = (3/2) k T

where, k = 1.38 x 10^-23 J/K

T = temperature = 90 ⁰C = 363 K

then, we have

K.E = (3/2) (1.38 x 10^-23 J/K) (363 K)

K.E = 751.4 x 10^-23 J

K.E = 7.51 x 10^-21 J

Question-10 : Her initial moment of inertia was given as -

using conservation of angular momentum,

I₁$\omega$₁ = I₂$\omega$₂

I₁ (9.42 rad/s) = (0.88 kg.m²) (25.1 rad/s)

I₁ = (22.08 kg.m² rad/s) / (9.42 rad/s)

I₁ = 2.35 kg.m²