For the reaction NH4Cl(aq) NHj(g) + HCl(aq) ??? = 86.4 kJ and ? S°-79.1 J/K AG°...

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Answer 1

Answer #1

1) DG0 = DH0-TDS0

at equilibrium,DG = 0

0 = 86.4-(x*79.1*10^-3)

x = T = 1092.3 k

above 1092.3 k ,DG0 will be -ve.(spontaneous)

2)

DG0 = DH0-TDS0

at equilibrium,DG = 0

0 = 98.8-(x*143*10^-3)

x = T = 690.91 k

above 690.91 k , DG0 will be -ve.(spontaneous)

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Answer 2

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