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For the reaction C2H4(g) + H2O(g)CH3CH2OH(g) H° = -45.6 kJ and S° = -126 J/K G°...

For the reaction C2H4(g) + H2O(g)CH3CH2OH(g) H° = -45.6 kJ and S° = -126 J/K G° would be negative at temperatures (above, below) K. Enter above or below in the first box and enter the temperature in the second box. Assume that H° and S° are constant.

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Answer #1

There is the equation of free energy change:

ΔG = ΔH - T * ΔS

0 = - 45.6 - T * (-0.126)

The critical temperature is cleared:

T = 362 K

At temperatures lower than 362 K, the free energy change is negative.

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