Given that x^n is inversely proportional to y and y is a quarter of its original value when x is doubled, calculate the value of n.
We have xn = k/y where k is the constant of proportionality. Hence y = k/xn.
Aso y/4 = k/(2x)n so that y = 4k/(2n *xn).
Therefore, k/xn = 4k/(2n *xn) or, (2n *xn)/ xn = = 4k/k or, 2n = 4 = 22.
Hence n = 2.
Given that x^n is inversely proportional to y and y is a quarter of its original...
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Solving variation problem
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