Question

An electron accelerates across the plates of a capacitor in 1.61 μs. The plates are separated by 1.89 mm. What current does the motion of this electron represent?

Answer 1

time t = 1.61 μs

plates separation d = 1.89 mm

electron charge

q=1.602 x 10-19

current does the motion of this electron is

$I = \frac{q}{t}$

I= 1.602 x 10-19 1.61 x 10-6S

I = 9.95 X 10-14 A