Question

Suppose a plant puts out a new shoot, and that shoot has to grow two months...

Suppose a plant puts out a new shoot, and that shoot has to grow two months before it is strong enough to support branching. If it branches every month after that at the growing point, write a recursion equation to describe number of branches after n months, B(n), and find its closed form, where B(1) = 1 and B(2) = 1.

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Answer #1

A recursion equation is an equation that expresses each element of a sequence as a function of the preceding ones. after growing point i.e from 3rd month onward the no of branch will be 1 more in the next month, however for 1 and 2 branching will be just 1, this can be written in recersion equation as follows:

B(N) = \begin{Bmatrix} 1& if N = 1 & \\ 1 & if N = 2 & \\B(N - 1) + 1& if N \geqslant 3 \end{Bmatrix}

a recursive fuction for this can be written as:

 void int numBranch(int numMonth){ if(numMonth == 1 || numMonth == 2){ return 1; } return numBranch(numMonth - 1) + 1; }

  

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