A train slows down at a constant rate as it rounds a sharp circular horizontal turn....

Question

Question

science physics

Answer 1

Answer #1

125 ts So tohl acelerf^_ o.an-t l.28다? レ叫

Answer 2

Similar Homework Help Questions

A train slows down as it rounds a sharp horizontal turn, going from 88.0 km/h to...

A train slows down as it rounds a sharp horizontal turn, going from 88.0 km/h to 56.0 km/h in the 13.0 s that it takes to round the bend. The radius of the curve is 160 m. Compute the acceleration (both magnitude and direction) at the moment the train speed reaches 56.0 km/h. [Assume the train continues to slow down at this time at the same rate.]
Approaching one of the many sharp horizontal turns in the Monaco Grand Prix, an experienced Formula-1...

Approaching one of the many sharp horizontal turns in the Monaco Grand Prix, an experienced Formula-1 driver slows down from 150 km/h to 47.0 km/h while rounding the bend in 11.0 s. If the driver continues to decelerate at this same rate and the radius of the curve is 15.0 m, what is the acceleration of the car the moment that its speed reaches 47.0 km/h? (Enter the magnitude.) m/s2
A 1200-kg car rounds a circular turn of radius R, toward the right, moving at a...

A 1200-kg car rounds a circular turn of radius R, toward the right, moving at a constant speed of 10.0 m/s on a horizontal road. Its angular momentum about the center of the turn has magnitude 2.00 - 108kg. ma. a) (4p) What is the direction of the angular momentum of the car? b) (6p) What is the radius of the turn?

The fast French train known as the TGV (Train à Grande Vitesse) has a scheduled average...

The fast French train known as the TGV (Train à Grande Vitesse) has a scheduled average speed of 216 km/h. (a) If the train goes around a curve at that speed and the magnitude of the acceleration experienced by the passengers is to be limited to 0.050g, what is the smallest radius of curvature for the track that can be tolerated? (b) At what speed must the train go around a curve with a 1.31 km radius to be at...
A 1450-kg car rounds a circular turn of radius 140 m, toward the left, on a...

A 1450-kg car rounds a circular turn of radius 140 m, toward the left, on a horizontal road. Its angular momentum about the center of the turn has magnitude 3.16×106kg⋅m2/s. What is the speed of the car?
A train is rounding a circular curve whose radius is 1.89E+2 m. At one instant, the...

A train is rounding a circular curve whose radius is 1.89E+2 m. At one instant, the train has an angular acceleration of 1.21E-3 rad/s2 and an angular speed of 0.0544 rad/s. Find the magnitude of the total acceleration (centripetal plus tangential) of the train.

When a high-speed passenger train traveling at vP = 158 km/h rounds a bend, the engineer...

When a high-speed passenger train traveling at vP = 158 km/h rounds a bend, the engineer is shocked to see that a locomotive has improperly entered onto the track from a siding and is a distance D = 692 m ahead (see the figure). The locomotive is moving at vL = 30 km/h. The engineer of the passenger train immediately applies the brakes. Assume that an x axis extends in the direction of motion. What must be the constant acceleration...
A racing car travels with a constant tangential speed of 75.0 m/s around a circular track...

A racing car travels with a constant tangential speed of 75.0 m/s around a circular track of radius 625 m. Find |(a) The magnitude of the car's total acceleration and |(b) The direction of its total acceleration relative to the radial direction.
A car is makes a sharp turn. The car enters the turn with speed 6.0 m/s...

A car is makes a sharp turn. The car enters the turn with speed 6.0 m/s and leaves the turn with speed 15.2 m/s after 5 seconds. At one point during the turn, the centripetal acceleration is 1.7 m/s2. What is the magnitude of the total acceleration at this point? Answer in m/s2.

At a time t 2.90 s, a point on the rim of a wheel with a radius of 0.240 m has a tangential speed of 50.0 m/s as the wheel slows down with a tangential acceleration of constant magnitude 10.2 m/s2.

At a time t 2.90 s, a point on the rim of a wheel with a radius of 0.240 m has a tangential speed of 50.0 m/s as the wheel slows down with a tangential acceleration of constant magnitude 10.2 m/s2. Part A Calculate the wheel's constant angular acceleration Part B Calculate the angular velocity at t 2.90 s Part C 0. Calculate the angular velocity at t =0 Part D Through what angle did the wheel turn between t = 0 and t...