Question

Please help step by step with problem 20. Thanks.
The Second Shifting Theorem Replacing g() by g(1 – t) in Theorem 8.4.1 yields the next theorem. Theorem 8.4.2 (Second Shifting Theorem Ift > 0 and L(8) exists for s > So then L (ult – t)g(1 – t)) exists for s > 50 and Luſt - t)g(t – t)) = e-"L()). or, equivalently, ifgt) G(s), then uſt - t):(t – t) e "G(s). (8.4.12) REMARK: Recall that the First Shifting Theorem (Theorem 8.1.3 states that multiplying a function by et corresponds to shifting the argument of its transform by a units. Theorem 8.4.2 states that multiplying a Laplace transform by the exponential es corresponds to shifting the argument of the inverse transform by t units.

Answer 1

Daiven és HLs)= s(sal) HLS) ens Now, Slstu) es es - HLs). S sal Applying Inverse Laplace Transform, then h+] = ['| HLS)}L'les ce es sti 2. >>ht) = 1.8Lt-1)-e-t-il.glt-1) & hlt)= [l-ett-o] sitt glt-) LE-i)).glt -i) h(t)= (relt. Answex