Question
consider a simple harmonic oscilator and its normalised eigenstates

Problem 5. Consider operators B and C, whose matrix representations in some basis are: ſo 10] [1ool 1 0 1 C=o oo Too-1 0 1 0
0 0
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Answer #1

Solution:

(a)

Since \small C is diagonal, we are in the \small C basis and the diagonal elements are the \small C eigenvalues, we have  \small C \pm 1,0.

(b)

The corresponding eigenvectors are:

\small |C=1>=\begin{pmatrix} 1\\ 0\\ 0\\ \end{pmatrix}=|1>

\small |C=-1>=\begin{pmatrix} 0\\ 0\\ 1\\ \end{pmatrix}=|-1>

C = 0 >= 1 0 = 10 >

(c)

\small \left \langle B \right \rangle=<1|B|1>=\left ( 1,0,0 \right )\frac{1}{\sqrt{2}}\begin{pmatrix} 0 & 1 & 0\\ 1 & 0 & 1\\ 0 & 1 & 0 \end{pmatrix}\begin{pmatrix} 1\\ 0\\ 0\\ \end{pmatrix}=0

\small \left \langle B^{2} \right \rangle=<1|B^{2}|1>=\left ( 1,0,0 \right )\frac{1}{2}\begin{pmatrix} 1 & 0 & 1\\ 0 & 2 & 0\\ 1 & 0 & 1 \end{pmatrix}\begin{pmatrix} 1\\ 0\\ 0\\ \end{pmatrix}=\frac{1}{2}

(d)

We have

\small |d>=\frac{1}{\sqrt{2}}|C=1>-\frac{i}{\sqrt{2}}|C=0>+0|C=-1>

\small P(C=1|d)=|<C=1|d>|^{2}=\frac{1}{2}

\small P(C=0|d)=|<C=0|d>|^{2}=\frac{1}{2}

\small P(C=-1|d)=|<C=-1|d>|^{2}=0

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