A 130.0 mL sample of a solution that is 2.8time 10^-3 M in AgNO, is mixed...

Question

Question

science chemistry

Answer 1

Answer #1

no of moles of AgNO3 = molaity * volume in L

= 0.0028*0.13

= 0.000364moles

no of moles of NaCN = molarity * volume in L

= 0.12*0.23 = 0.0276moles

Ag^+(aq) + 2CN^- ----------------->[ Ag(CN)2]^-

I 0.000364 0.0276 0

C -0.000364 2*-0.000364 0.000364

E 0 0.026872 0.000364

Kf = [Ag(CN)2]^-/[Ag^+][CN^-]^2

5.6*10^18 = 0.000364/x*(0.026872)^2

x = 0.000364/(5.6*10^18)(0.026872)^2 = 9*10^-20

[Ag^+] = 9*10^-20/0.13 = 6.92*10^-19 M

Answer 2

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