Homework Answers
Answer:
aaBbccDdEE x AaBbCcDdEe ---Parents
aa x Aa = Aa (1/2) & aa (1/2)
Bb x Bb = BB (1/4), Bb (1/2) & bb (1/4)
cc x Cc = Cc (1/2) & cc (1/2)
Dd x Dd = DD (1/4), Dd (1/2) & dd (1/4)
EE x Ee = EE (1/2) & Ee (1/2)
A). Genotype of the first parent = aaBbccDdEE = ½ * ½ * ½ * ½ * ½ = 1/32
B). Phenotype of the second parent = A_B_C_D_E_ = ½ * ¾ * ½ * ¾ * 1 = 9/64
C). Genotype of: AaBbCcDdEe = ½ * ½ * ½ * ½ * ½ = 1/32
D).
Parent 1: aaB_ccD_E_ = ½ * ¾ * ½* ¾ * 1 = 9/64
Parent 2: A_B_C_D_E_ = ½ * ¾ * ½ * ¾ * 1 = 9/64
Proportion with either parental phenotype = 9/64 + 9/64 = 18/64 = 9/32
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