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What would be the final Cu^+ concentration in a soIf you could please explain and give detailed on how you got this answer thanks.

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Answer #1

Ans: CuI <====> Cu+ + I-

x x

PbI2 <=====> Pb+2 +2I-

0.1 2 x 0.1

Cu+ =x , I- = 2 x 0.1 = 0.2M

Ksp = [Cu+] [I-]

5.1 x 10-12 =   [Cu+] (0.2)

  [Cu+] = 25.5 x 10-12

     

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