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The coefficient of static friction between the flat bed of the truck and the crate it carries is 0.29. Determine the minimum stopping distance s which the truck can have from a speed of 50 km/h with constant deceleration if the crate is not to slip forward.

The coefficient of static friction between the flat bed of the truck and the crate it carries is 0.29. Determine the minimum

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ANSWER - Given that * M = 0.29 * v - 50 km/h velocity changing into mtr/sec V = 50 X 1000 3600 V - 50000 - 3600 V = 13.88 mtr> 52vF/2.99) , * minimum stopping distance - vr (19) * Gravity value = 9.81 13.s)/(zx0.1949.81) ( 92.65 介介、介 2x0.81x 0.29 | 1

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