Question

The output voltage of an AC generator is given by

Δv = (1.01 ✕ 10² V)sin(39πt).

The generator is connected across a 0.500 H inductor. Find the following.

(a) frequency of the generator
Hz

(b) rms voltage across the inductor
V

(c) inductive reactance
Ω

(d) rms current in the inductor
A

(e) maximum current in the inductor
A

(f) average power delivered to the inductor
W

(g) Find an expression for the instantaneous current. (Use the following as necessary: t.)

i

=

(h) At what time after

t = 0

does the instantaneous current first reach 1.00 A? (Use the inverse sine function.)
ms

Answer 1

DV= (1.01X102 V) sim 39 at) ferent = 395 = 19.5 HZ 69 XL = WL = (39^ )(0.5) - (19.56) e Vmax = 101x0²y Verans = 1.01X102 = 0.71X102 V V2 V2 titled within 1 year Tans s you to her .16A 2 0.71 2 u16A (la e) Imax = 12 Iams = 11 (15) = 1.64A