Question

Let Z be the standard normal variable. Find z if z satisfies the given value. (Round your answer to two decimal places.) P(Z > 2) = 0.9535 z =

Answer 1

P[22] 0.9535 P[252] 1-0.9535 20.0465 => $(2) - 0.0465 .). (-2) 1-$(2): 0.9535 2 (168) - Z = 1.68 -89.1-32 Let x lee the the score obtained to be eligible 8. P(x), 75]. P[*70 ) 75+) = P. [21] 1-P[2<1] = 10.8 41 3447 0.15896. qualifying 8. % of applicants roho passed the written examination : 41587 X100.. = 15.87").

Let x denotes the score of economees oamination P[.x>>] .. [xx): 0.9 [* }<20-**]05. 2) P[2<**] -09 (127) 3) (*) - (127) 3) *178 - 12 IS IS - 23 78 + 15x1.29. 2 x. 97.35 The lowest scoon a students have in 97.35.