Let Z be the standard normal variable. Find z if z satisfies the given value. (Round...

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Let Z be the standard normal variable. Find z if z satisfies the given value. (Round...

Let Z be the standard normal variable. Find z if z satisfies the given value. (Round your answer to two decimal places.) P(−z < Z < z) = 0.9802

math Statistics-And-Probability

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Answer 1

Answer #1

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P(-z < Z < z) =0.9802

P(Z < z) - P(Z < -z) = 0.9802

2 P(Z < z) - 1 =0.9802

2 P(Z < z) = 1 + 0.9802. = 1.9802

P(Z < z) = 1.9802 / 2 = 0.9901

P(Z < 2.33) = 0.9901

z ± 2.33 using z table

z= -2.33 , z= + 2.33

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Answer 2

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