(a)
Z for 125 will be
(125-100)/15 = 1.66666666667
P ( Z > 1.66666666667) = 0.047790352 { use the excel function =1-NORM.S.DIST(1.66666666667,TRUE)}
(b)
Z for 90
(90-100)/15 = -0.66666666666
P( Z < -0.66666666666) = 0.252492538 { Use the excel function =NORM.S.DIST(-0.66666666667,TRUE)}
(c)
Z for 110 is 0.666666666
Z for 140 = 40/15 = 2.666666
P ( 0.666666 < Z < 2.666666 ) = P ( Z < 2.66666666) - P(Z < 0.6666666) = 0.2487
(d) Z for 150 is
50/15 = 3.3333333
P ( Z > 3.33333) = 0.0004
r Intelligence Scale The Wechsler Intelligence Scale or Children is approximately normally distributed, with mean for...
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