Question

At 310 K, the partial vapor pressures of a substance B dissolved in a liquid A are as follows: Show that the solution obeys Henry's law in this range of mole fractions, and calculate Henry's law constant at 310 K.

Answer 1

Henry's law: According to Henry's law at my given teperature the solubility of gas is directly proportional to its partial pressure. Here; C concuntration of gas にproportionality constant P- partial pressure PI. At 310 K, the partial vapor pressures of a subsance B d follows: Pn (kPa 82.0 Show that the solution obeys Henry's law in this range of mole fractions, and cakulae 0010 0,015 122.0 0.020 166.1 Henry's law constant at 310 K Here According to the Henry Law Partial pressure-Henry Costant mole Fraction Therefore We may plot рв vsXp and look at the limiting slope by fitting the data to a low order polynomial. Such a plot is given below Since the data appears to closely fit a straight line means This gives the result that Henry Law is Valid 82.0-k#0.010 k 8200 atm mol The ratio (p/x) approx remains Con This gives the result that Henry Law is Valid Plot of pB vs Xb 200 160 120 m 80 40 0.005 0.015 FromSecon ХВ k-px- 122.0 0.015 -8133.33 atm/mole For Third k = p/X = 1 66 . 1/0.020 -8305 atm/mole Thereofre Kreqd Average of three values of k - (8200 8133.33+8305)3 - 8212.78 atm /mole