Question

A dipole is centered at the origin, and is composed of charged particles with charge +e and -e, separated by a distance 9 times 10^-10 m along the y axis. The +e charge is on the -y axis, and the -e charge is on the +y axis. A proton is located at < 0, 1 times 10^-8, 0 > m. What is the force on the proton, due to the dipole? F vector = N An electron is located at < -1 times 10^-8, 0, 0 > m. What is the force on the electron, due to the dipole? F vector = N

Answer 1

a) We have the force due to the dipole Here electricfieldis given by 2kP P-qd = 1.6×10-19×9×10-10 =14.4×10-3 (1x1) = 2592000N / C 1.6 x 10-19 2592000 =4.14x10-13 N b) Here electric field is perpendicular bisector due to dipole.So the electric field here is

Hereelectricfieldis given by kP 1.6x10-19 x9x10-10 14.4x10 9x10, x14.4 x10-29 1x10-5 = 1 296000N/ C 1.6×10-19×1296000 = 2.07 x 10-13N