100 mL of 0.2M aqueous solution of some organic compound was brought in contact with 5...
100 mL of 0.2M aqueous solution of some organic compound was brought in contact with 5 mL of heptane at 20 oC. GC analysis of heptane phase after equilibration shows component concentration of 0.12 M. What is the partitioning coefficient of this component?
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100 mL of 0.2M aqueous solution of some organic compound was
brought in contact with 5...
100 mL of aqueous solution containing 2,4,6-trinitrotoluene (TNT) at an initial concentration of 0.05 ppm is...
100 mL of aqueous solution containing 2,4,6-trinitrotoluene (TNT) at an initial concentration of 0.05 ppm is shaken with 10 mL hexane. After the phase separation, it was determined that the organic phase has 0.4 ppm. What is the partition coefficient, and what is the percent extracted? If the equilibrium concentration (rather than initial concentration) is 0.05 ppm, this would simplify the calculation. What would then be the partition coefficient and percent extracted? (Please answer or provide something for the second...
You are in possession of an organic compound that is 0.40 M in a 200.0 mL...
You are in possession of an organic compound that is 0.40 M in a 200.0 mL aqueous sample. You are tasked with extracting this compound into 100 mL of hexane. Describe what you will do to maximize the extraction from aqueous to organic phase and provide example calculations for the final amount remaining the aqueous phase after your extraction.
4) Two beakers, A and B, contain a 50 mL solution of 0.10 M aqueous urea and a 50 mL solution of ...
4) Two beakers, A and B, contain a 50 mL solution of 0.10 M aqueous urea and a 50 mL solution of 0.20 M aqueous urea, respectively. The two beakers are placed in a completely sealed box at 298 K and the system is left to equilibrate for a year. What are the contents of the two beakers after equilibration? (Assume that the vapor pressure of urea is small enough to be ignored and that the box is small enough...
Consider 15 mL of an aqueous solution containing 2.0 g of an organic solute.If the distribution...
Consider 15 mL of an aqueous solution containing 2.0 g of an organic solute.If the distribution coefficient for the solute between ether and water is 20, calculate the percent of the compound that can be recovered with a single extraction with 26.8 mL of ether. (2 sig figs)
5) A 100.0 mL aqueous solution containing 2.50 g of compound Z results is extracted with...
5) A 100.0 mL aqueous solution containing 2.50 g of compound Z results is extracted with 25.0 mL of ethyl acetate. The ethyl acetate is evaporated to yield 0.95 g of compound Z. 4 points Calculate the partition coefficient (also known as the distribution coefficient) K, for compound Z in ethyl acetate and water, where K = (concentration of Z in diethyl ether) + (concentration of Z in water): Calculations Answer
Question1: Multiple Choice: circle the best answer (3 points) 150 mL of an aqueous analyte solution...
Question1: Multiple Choice: circle the best answer (3 points) 150 mL of an aqueous analyte solution is extracted five times with 50 mL of ether (an organic solvent). The partition constant K for the analyte is 1.99. If the starting solution is 1.00 M in analyte concentration, what is the concentration of analyte remaining in the aqueous layer after the 5th extraction? a. (i) 0.07 (ii) 0.12 (iii) 0.19 (iv) 0.22 (v) 0.26 b. Reverse-phase chromatography has what type of...
The extraction of 8.0 g of a particular organic compound dissolved in 100 ml of water...
The extraction of 8.0 g of a particular organic compound dissolved in 100 ml of water into diethyl ether proceeds with a distribution coefficient of 5. How much of the compound is extracted after three separate extractions using 50 ml of diethyl ether each time? ***Please show work as I am not 100% sure how to solve for X**** Thank you!
The partition coefficient, K, for compound A between toluene and water is 7.25. What is the...
The partition coefficient, K, for compound A between toluene and water is 7.25. What is the concentration of compound A remaining in the aqueous phase after 40.0 mL of 0.205 M A is extracted with each quantity of toluene indicated? one 35.0 mL portion: [A]= two 17.5 mL portions: (A)2 = five 7.00 mL portions: [A]g = ten 3.50 mL portions: [A] 20 =
A monoprotic acid (Ka = 4.31 x 10-5) has a partition coefficient of 4.4 in favor of octanol) when distributed between w...
A monoprotic acid (Ka = 4.31 x 10-5) has a partition coefficient of 4.4 in favor of octanol) when distributed between water and octanol. Find the concentration of the acid remaining in the aqueous phase when when 100 mL of 0.10 M aqueous solution of the acid is extracted with 27 mL of octanol at pH 4.00. a. 0.17 M b.0.546 M OC. 0.01 M o d. 0.0546 M
Mass transfer questions. QUESTION 2 [20 MARKS] Ammonia (A) - water (B) solution is in contact...
Mass transfer questions.
QUESTION 2 [20 MARKS] Ammonia (A) - water (B) solution is in contact at a surface with an organic liquid at 278 K. The concentration of ammonia in the organic phase is 10 wt%, and the density of aqueous solution is 961.7 kg/m². Meanwhile, the concentration of ammonia in water at the other end of the film at 5.4 mm away is 2.5 wt%, and the density is 991.7 kg/m². The flux of ammonia and the water...
4) Two beakers, A and B, contain a 50 mL solution of 0.10 M aqueous urea and a 50 mL solution of 0.20 M aqueous urea, respectively. The two beakers are placed in a completely sealed box at 298 K and the system is left to equilibrate for a year. What are the contents of the two beakers after equilibration? (Assume that the vapor pressure of urea is small enough to be ignored and that the box is small enough...
5) A 100.0 mL aqueous solution containing 2.50 g of compound Z results is extracted with 25.0 mL of ethyl acetate. The ethyl acetate is evaporated to yield 0.95 g of compound Z. 4 points Calculate the partition coefficient (also known as the distribution coefficient) K, for compound Z in ethyl acetate and water, where K = (concentration of Z in diethyl ether) + (concentration of Z in water): Calculations Answer
Question1: Multiple Choice: circle the best answer (3 points) 150 mL of an aqueous analyte solution is extracted five times with 50 mL of ether (an organic solvent). The partition constant K for the analyte is 1.99. If the starting solution is 1.00 M in analyte concentration, what is the concentration of analyte remaining in the aqueous layer after the 5th extraction? a. (i) 0.07 (ii) 0.12 (iii) 0.19 (iv) 0.22 (v) 0.26 b. Reverse-phase chromatography has what type of...
The partition coefficient, K, for compound A between toluene and water is 7.25. What is the concentration of compound A remaining in the aqueous phase after 40.0 mL of 0.205 M A is extracted with each quantity of toluene indicated? one 35.0 mL portion: [A]= two 17.5 mL portions: (A)2 = five 7.00 mL portions: [A]g = ten 3.50 mL portions: [A] 20 =
A monoprotic acid (Ka = 4.31 x 10-5) has a partition coefficient of 4.4 in favor of octanol) when distributed between water and octanol. Find the concentration of the acid remaining in the aqueous phase when when 100 mL of 0.10 M aqueous solution of the acid is extracted with 27 mL of octanol at pH 4.00. a. 0.17 M b.0.546 M OC. 0.01 M o d. 0.0546 M
Mass transfer questions.
QUESTION 2 [20 MARKS] Ammonia (A) - water (B) solution is in contact at a surface with an organic liquid at 278 K. The concentration of ammonia in the organic phase is 10 wt%, and the density of aqueous solution is 961.7 kg/m². Meanwhile, the concentration of ammonia in water at the other end of the film at 5.4 mm away is 2.5 wt%, and the density is 991.7 kg/m². The flux of ammonia and the water...
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