Question

pleas check all work and explain all steps & constants! please check units as well, thank you!

2) A solenoid passes through the x-y plane. A charge of -4 Coulombs with a mass of 4 x 107kg moving at 40 m/s (in the kv plane) is placed in the solenoid. Due to the magnetic field produced by the solenoid, the charge moves clockwise in a radius of 2 meters. The charge is removed anda circular wire wound 3 times with a radius of 6 meters is placed in the solenoid. If the total magnetic field at the center of the circular is zero, what is the amount and direction of the current in the circular wire in amps? Indicate clockwise by a negative sign (negative answer) and don't enter a sign for counter-clockwise. solenoid solenoid Cireular wirc -9

Answer 1

Initial magnitude field inside the solenoid r = mv/q so B = mv/qr rightdoublearrow 4 times 10^-7 times 14/ - 4 times 2 B = -20 times 10^-7 T For net magnetic field at the couter to Be zero magnetic field due to wire should Be equal and opposite to the above magnetic field so + 20 times 10^-7 = mu_0 n I/sR I = 20 times 2 times 4 times 10^-7/3 times 4 pi times 10^-7 I = 4.2441 amp This is opposite to the magnetic field due to solenoid so it must beta clock wise