Question

An uncharged capacitor with C-14.9 μF, a resistor with R = 24.3 kQ. and a battery with V= 25.7 V are connected in series as shown in the figure What is the charge on the capacitor at t= 0.3621 s after the switch is closed? a) 5.48 10-5 C b) 7.94 10-5 C c) 1.15 10-5 C d) 1.66 10-4 C e) 2.42 10-4 C ーC

The answer is e, details plz ?

Answer 1

Here ,

time constant of the circuit , T

T = R*C

T = 14.9 *10^-6 * 24.3 *10^3

T = 0.3621 s

the time taken is 0.3621 s

charge on the capacitor , Q = Qo *(1 - e^(-t/T))

charge on the capacitor , Q = 25.7 * 14.9 *10^-6 *(1 - e^-1)

charge on the capacitor , Q = 2.42 *10^-5 C

the charge on the capacitor is e) 2.42 *10^-5 C