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Question 10 10 pts During the turning of a 40 in long bar, cutting diameter is reduced from 8 in to 7.6 in. The tool is trave

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Answer #1

pecific cutting energy = power required/Material removal rate

Material removal rate =pi/4*(di2-df2)*feed velocity =3.14/4*(82-7.62)*9 =44.107 in3/min

so power required = 2*44.107 = 88.2159 hp

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