Question

What value is printed out from the code below?

public void square(double x) {
double x = x * x;
}
:
double val = 10;
square(val);
System.out.println(val);

Answer 1

Champ the above code needs some modification so that it functions appropriately.

Firstly, let us consider the statement double x = x * x;

You cannot store the resultant value(x*x) in x because it's already declared over here public void square(double x).

Secondly, the codehas to be implemented within the class.

The method public void square(double x) does not retrun any value. Hence either you have to print the output within the function or you can return the output to the function call.

From a static main function you cannot call a non-static method. Therefore the function public void square has to be implemented as a static one.

The code and it's output are shown below...

class Demo

{

public static void square(double x)

{

double y = x * x;

System.out.println(y);

}

  

public static void main(String args[])

{

double val = 10;

square(val);

}

  

}