Vitamin A (MM=286.4516 g/mol) was measured by an electrochemical technique. 28.0 mL of carrot juice...
Vitamin A (MM=286.4516 g/mol) was measured by an
electrochemical technique.
28.0 mL of carrot juice is diluted to 96.90 mL and the detector
current was measured to be 30.0 µA.
27.0 mg of vitamin A and 28.0 mL of carrot juice are diluted to
96.90 mL and the detector current increased to 69.5 µA.
Calculate the concentration of vitamin A in carrot juice in units
of ppm.
How to find concentration of Vit A added in the spike sample?
please solve it all.
Homework Answers
Molecular weight of VitaminA is : 286.4516 gr/mol
According to given data, 27mg of VitaminA is added to 28ml of carrot juice and dilute 96.9 ml
Therefore concentratiion of VitaminA in carrot juice is ,
M =(Wt/Mwt) * 1/V(L)
=0.97 ppm
=
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Vitamin A (MM=286.4516 g/mol) was measured by an
electrochemical technique.
28.0 mL of carrot juice...
Vitamin C (MM=176.12 g/mol) was measured by an electrochemical technique. 2400 µL of lemon juice...
Vitamin C (MM=176.12 g/mol) was measured by an electrochemical technique. 2400 µL of lemon juice is diluted to 12.50 mL and the detector current was measured to be 28.88 mA. 1.800 mmol of vitamin C and 2400 µL of lemon juice are diluted to 12.50 mL and the detector current increased to 59.30 mA. Calculate the concentration of vitamin C in lemon juice in units of mmol/L (mM).
measured concentration of vitamin C in fruit juice. ( mol/L) Type of juice Ppple Volume of...
measured concentration of vitamin C in fruit juice. (
mol/L)
Type of juice Ppple Volume of container: 200mL Volume per serving: aob mL Servings per container: % RDA of vitamin C per serving: 1007 Calculated concentration of vitamin C based on packaging: RDA for vitamin C: 90 mg O.45 mg/mL 2.55X 10o ,mol/L Calculated molar concentration of vitamin C based on packaging: (assume molar mass is equal to that of ascorbic acid, 176.12 g/mol) Titration Data: 0.00Sm Concentration of lodine...
Ascorbic acid (vitamin C, MM 176.124 g/mol)) can be determined using an iodometric back titration. A...
Ascorbic acid (vitamin C, MM 176.124 g/mol)) can be determined using an iodometric back titration. A vitamin C tablet was dissolved in 60 mL of 0.3 M H2S04. To the dissolved tablet, 2 g of KI and 50.00 mL of 0.0105 M KIO3 were added, resulting in the formation of a dark orange solution indicating the presence of 13-. The resulting solution was titrated with 0.0685 M S2032- until the starch indicator turned purple. If the end point was observed...
If you dissolve 412 mg sucrose (formula weight: 342.29 g/mol) in 60 mL of water: a. What is the concentration of sucrose in mM in µM? b. If you take 5 mL of this solution and dilute it to 250 mL, what...
If you dissolve 412 mg sucrose (formula weight: 342.29 g/mol) in 60 mL of water: a. What is the concentration of sucrose in mM in µM? b. If you take 5 mL of this solution and dilute it to 250 mL, what is the concentration of the glucose in the resulting solution in µM? c. How many nano moles of sucrose are present in 10 mL of the diluted solution?
measured concentration of vitamin C in fruit juice. (
mol/L)
Type of juice Ppple Volume of container: 200mL Volume per serving: aob mL Servings per container: % RDA of vitamin C per serving: 1007 Calculated concentration of vitamin C based on packaging: RDA for vitamin C: 90 mg O.45 mg/mL 2.55X 10o ,mol/L Calculated molar concentration of vitamin C based on packaging: (assume molar mass is equal to that of ascorbic acid, 176.12 g/mol) Titration Data: 0.00Sm Concentration of lodine...
Ascorbic acid (vitamin C, MM 176.124 g/mol)) can be determined using an iodometric back titration. A vitamin C tablet was dissolved in 60 mL of 0.3 M H2S04. To the dissolved tablet, 2 g of KI and 50.00 mL of 0.0105 M KIO3 were added, resulting in the formation of a dark orange solution indicating the presence of 13-. The resulting solution was titrated with 0.0685 M S2032- until the starch indicator turned purple. If the end point was observed...
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