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a) Calculate K at 298 K for the following reaction: NO(g) + 1 2 O2(g) ?...

a) Calculate K at 298 K for the following reaction:

NO(g) +

1

2

O2(g) ? NO2(g)

?G0f(kj/mol)
NO(g) 86.60
NO2(g) 51
O2(g) 0


K = ×10

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Answer #1

ANSWER:

we know that,

?G° = ? ?Gf°(products)– ? ?Gf°(reactants)

?G° = {51.0 - (86.60 + 0.0)} kJ/mol

?G° = - 35.60 kJ/mol = 3.56 x 104 J/mol

and, relation between ?G° and K is:

?G° = - 2.303 RT log K

-3.56 x 104 J/mol = - 2.303 x 8.314 J/K-mol x 298K x log K

log K = 6.24

K = 1.74 x 106

Hence, K at 298 K for the following reaction is 1.74 x 106.

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