Question 9:
x.x = x
Answer: True
Question 10:
The Boolean function F(x,y,z) = (y+x)(y+x1)(y1+z) is equivalent to:
Answer: yz
Explanation:
(y+x)(y+x1)(y1+z)
= (y.y+yx1+xy+x.x1)(y1+z)
= (y+yx1+xy+0)(y1+z) [ since y.y = y and x.x1 = 0 ]
= (y+xy)(y1+z) [ since y+yx1 = y ]
= (yy1+yz+xy.y1+xyz)
= (0+yz+0+xyz) [ since y.y1 = 0 ]
= (yz(1+x)
= yz [ since 1+x = 1 ]
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