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Suppose you begin with 2.4 moles of sodium and 1.4 moles of fluorine. Calculate the moles...

Suppose you begin with 2.4 moles of sodium and 1.4 moles of fluorine. Calculate the moles of product that can be made from each reactant. 2Na+F2-----2NaF, limiting reactant and theoritical yield of NaF in grams? Please help me!!!

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Answer #1

                   2Na+F2-----2NaF

                2 moles of Na react with 1 mole of F2

                2.4 moles of Na react with = 2.4/2 = 1.2 moles F2

                  Na is limiting reactant

                  F2 is excess reactant

           2 moles of Na react with F2 to form 2 moles of NaF

          2.4 moles of na react with F2 to form = 2*2.4/2 = 2.4 moles of NaF

       mass of NaF = no of moles * gram molar mass

                            = 2.4*42 = 100.8g

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