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35. Calculate ΔrH° for the combustion of ammonia, 4 NH3(g) + 7 O2(g) → 4 NO2(g)...
Question 17 3 pts Using standard molar enthalpies of formation given in the table below, calculate AH/xnto one decimal place, for the combustion of ammonia: AHrxn° = E nAH (products) - E mAHt"reactants) 4 NH3(g) + 7 O2(g) → 4NO2(g) + 6H2O(1) molecule AHF (kJ/mol-rxn) NH3(g) -45.9 NO2(g) +33.1 H2O(1) -285.8 H2O(9) -241.8 - 1663.6 kJ/mol-rxn +30.24 kJ/mol-rxn -1398.8 kJ/mol-rxn -298.6 kJ/mol-rxn -206.9 kJ/mol-rxn Question 11 3 pts A gas absorbs 45 kJ of heat and does 29 kJ of...
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Determine the heat of reaction for the combustion of ammonia 4NH3(g)+702(g)-»4NO2(g) + 6H20() using molar enthalpies of formation AH° (kJ/mol) 45.9 molecule NH3(g) NO2(g) H2O() +33.1 -285.8 a. +30.24 kJ b. -206.9 kJ c. -298.6 kJ d. -1398.8 kJ e. -1663.6 k ,Determine the heat...
Determine ΔrH° for the following reaction, 2 NH3(g) + 5/2 O2(g) → 2 NO(g) + 3 H2O(g) given the thermochemical equations below. N2(g) + O2(g) → 2 NO(g) ΔrH° = +180.8 kJ/mol-rxn N2(g) + 3 H2(g) → 2 NH3(g) ΔrH° = –91.8 kJ/mol-rxn2 2H2(g) + O2(g) → 2 H2O(g) ΔrH° = –483.6 kJ/mol-rxn a. –1178.2 kJ/mol-rxn b. –452.8 kJ/mol-rxn c. –394.6 kJ/mol-rxn d. –211.0 kJ/mol-rxn e. +1178.2 kJ/mol-rxn
a) Calculate the enthalpy of the reaction 2NO(g)+O2(g)→2NO2(g) given the following reactions and enthalpies of formation: 12N2(g)+O2(g)→NO2(g), ΔfH∘A=33.2 kJ mol−1 12N2(g)+12O2(g)→NO(g), ΔfH∘B=90.2 kJ mol−1 Express your answer with the appropriate units. b) Calculate the enthalpy of the reaction 4B(s)+3O2(g)→2B2O3(s) given the following pertinent information: B2O3(s)+3H2O(g)→3O2(g)+B2H6(g), ΔrH∘A=+2035 kJ mol−1 2B(s)+3H2(g)→B2H6(g), ΔrH∘B=+36 kJ mol−1 H2(g)+12O2(g)→H2O(l), ΔrH∘C=−285 kJ mol−1 H2O(l)→H2O(g), ΔrH∘D=+44 kJ mol−1
Standard Enthalpies of Formation, in kJ/mol N2(g) 0 NO2(g) +33.2 NH3(g) -45.9 H2O(l) -285.8 NO(g) +90.3 N2O(g) -82.1 H2O(g) -241.8 Use the data above to calculate ΔH for the reaction: 6 NO2(g) + 8 NH3(g) => 7 N2(g) + 12 H2O(g) ΔH = ?
The standard enthalpy change for the combustion of 1 mole of propane is -2043.0 kJ. CzH3(g) + 5 O2(g) + 3 CO2(g) + 4H2O(g) Calculate 4, Hº for propane based on the following standard molar enthalpies of formation. molecule CO2(g) H2O(g) 4,Hº (kJ/mol-rxn) -393.5 -241.8
For the combustion of cyclopropane at 25 ºC C3H6(g) + (9/2) O2(g) → 3 CO2(g) + 3 H2O(liq) ΔHºc(C3H6,g) = -2091 kJ / mol. What is the standard molar enthalpy of formation of cyclopropane(g) at 25 ºC if the standard molar enthalpies of formation of CO2(g) and H2O(liq) at that temperature are, respectively, -393.51 kJ / mol and -285.83 kJ / mol?
Consider the following chemical reaction and free energies of formation in the table: 4 NH3(g) + 7 O2(g) → 4 NO2(g) + 6 H2O(l) Calculate ∆G°rxn (kJ) for the reaction. Only enter a numerical value. Products or reactants ∆G°f, kJ/mol NH3(g) -17 O2(g) 0 NO2(g) +52 H2O(l) -237
Determine the enthalpy of formation (in kJ/mol) for NO2 (g), given the following reaction: 4 NH3 (g) + 7 O2 (g) 4 NO2 (g) + 6 H2O(l) rxnH° = –1400 kJ, fH°(NH3, g) = –46 kJ/mol, fH°(H2O,l) –286 kJ/mol. (1) +733 (2) +33 (3) +794 (4) –28 (5) –59
The combustion reaction of ethane is as follows. C2H6(g) + 7/2 O2(g) → 2 CO2(g) + 3 H2O(l) Using Hess's law and the reaction enthalpies given below, find the change in enthalpy for this reaction. reaction (1): C(s) + O2(g) → CO2(g) ΔH = −393.5 kJ/mol reaction (2): H2(g) + 1/2 O2(g) → H2O(l) ΔH = −285.8 kJ/mol reaction (3): 2 C(s) + 3 H2(g) → C2H6(g) ΔH = −84.0 kJ/mol