Cacodylic acid is a common weak acid

let we have V L of NaOH is used
then, number of mole = (molarity)*(volume in L)
number of mole of NaOH = 5V
then, number of mole of cacodylic acid = 0.1 mole
so,
5V mole of NaOH react with 5V mole of acid to form 5V mole of
salt
number of mole of acid remain = 0.1-5V
as volume for salt and acid remainig is same
molarity ratio of salt and acid remaing = number of mole of ratio
of salt and acid
use,
pH = pKa + log([salt]/[acid])
6.7 = 6.2 + log(5V/(0.1-5V))
log(5V/(0.1-5V)) = 0.5
5V/(0.1-5V) = 10^0.5
5V/(0.1-5V) = 3.16
5V = 3.16*(0.1-5V)
5V = 0.316 - 15.8V
20.8V = 0.316
V = 0.0152 L
= 15.2 mL
Answer : 15.2 mL
Cacodylic acid is a common weak acid Cacodylic acid is a common weak acid used to...
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Conjugate Base
Ka
pKa
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